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Input was: u:køq u:khaq. Searched Embree for u:køq u:khaq, found 3,
kerngkhaq/kexng-køhkhaq [wt] [HTB] [wiki] u: kexng(-køq)-khaq [[...]][i#] [p.131]
Int : still more increasingly
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køhkhaq [wt] [HTB] [wiki] u: køq'khaq [[...]][i#] [p.146]
Int : still more <koh-khah-choe7: still more>, <koh-khah-lam: still weaker>
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u: køq khaq axn'zvoar [wt] [HTB] [wiki] [[...]][i#] [p.146]
Pmod : no matter how
無論怎樣