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Searched Lim08 for 拗霸, found 1,
u: ax'pax 拗霸 [wt] [HTB] [wiki] [[...]][i#] [p.A0006]
gin2 - a2剛強e5個性 。 < gin2 - a2真a3 - pa3 = gin2 - a2個性橫pa3 - pa3 。 >