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Searched Lim08 for 破戒**, found 2,
u: phøx'kaix 破戒 [wt] [HTB] [wiki] [[...]][i#] [p.B0896] [#46880]
( 文 )<>
u: phoax'kaix 破戒 [wt] [HTB] [wiki] [[...]][i#] [p.B0870] [#46939]
( 1 )( 文 ) ( 2 ) ＝ [ 破phah ] 。 <>