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Input was: u:kii u:zeg. Searched Lim08 for u:kii u:zeg, found 2,
u: kii'zeg 奇跡 [wt] [HTB] [wiki] [[...]][i#] [p.A0271] [#32429]
（ 日 ） <>
u: kii'lie zeg'id 其理則一 [wt] [HTB] [wiki] [[...]][i#] [p.A0277] [#32492]
理由kan - ta一個 ， 結果仝款 。 <>