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Searched Lim08 for poah taau ar, found 1,
u: poah'taau'ar 博骰仔 [wt] [HTB] [wiki] [[...]][i#] [p.B0873] [#48436]
( 1 ) 用骰a2來poah8 - kiau2 。 ( 2 ) 使用骰a2 e5 poah8 - kiau2 。 <>