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Input was: u:phoax u:kaix. Searched for u:phoax u:kaix
Lim08 (1)
u: phoax'kaix 破戒 [wt] [HTB] [wiki] [[...]][i#] [p.B0870] [#46939]
( 1 )( 文 ) ( 2 ) = [ 破phah ] 。 <>