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Input was: u:long u:zuo. Searched Lim08 for u:long u:zuo, found 2,
u: long'zuo 浪子 [wt] [HTB] [wiki] [[...]][i#] [p.B1037] [#40581]
放蕩kiaN2 。 <∼∼ 回頭金不換 (= 比金khah價值 ) 。 >
u: long'tong'zuo 浪蕩子 [wt] [HTB] [wiki] [[...]][i#] [p.B1037] [#40597]
放蕩kiaN2 。 <>